hitunglah hasil kali kelarutan suatu senyawa M(OH)2 mempunyai pH=10
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hitunglah hasil kali kelarutan suatu senyawa M(OH)2 mempunyai pH=10
1 Jawaban
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1. Jawaban salllma01
pH = 14-10 = 2
pOH = -log 10^-2
[OH-] = 10^-2
[OH-] = b × Mb
10^-2 = 2 × Mb
Mb = 5×10^-3
s (kelarutan) = Mb
s = 5×10^-3
M(OH)2 -> M2+ + 2OH-
s s 2s
Ksp = [M2+] [2OH-]
Ksp = (s) (2s)²
Ksp = 4s³
Ksp = 4 (5×10^-3)³
Ksp = 4 (125×10^-9)
Ksp = 500×10^-9
Ksp = 5×10^-7