Matematika

Pertanyaan

1.limit mendekati tak hingga 6x^5 - 4x/ 2x²+x =
2.Limit mendekati tak hingga √4x²+7x+1 - √4x²-4x+1 =

1 Jawaban

  • Bab Limit
    Matematika SMA Kelas XI

    1] lim ((6x⁵ - 4x) / (2x² + x))
       x→∞
    = lim ((6x⁵/x⁵ - 4x/x⁵) / (2x²/x⁵ + x/x⁵))
      x→∞
    = lim (6 - 4/∞⁴) / (2/∞³ + 1/∞⁴)
      x→∞
    = (6 - 0) / (0 + 0)
    = 6 / 0
    = ∞

    2] lim (√(4x² + 7x + 1) - √(4x² - 4x + 1))
       x→∞
    a = 4; b = 7; c = 1; p = 4; q = -4; r = 1
    karena a = p = 4, maka

    (b - q) / (2 √a)
    = (7 - (-4)) / (2 √4)
    = 11 / (2 . 2)
    = 11/4


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