Hitunglah berapa molekul molekul yang terdapat dalam 6 gram glukosa (C6H12O6) jika di ketahui Ar C = 12,0 = 16, dan H = 1

diketahui
Gr C6H12O6 = 6 gram
Mr C6H12O6 = 180
Jawab
Gr C = x Ar C × Gr C6H12O6/Mr C6H12O6
Gr C = 6 × 12 × 6/180
Gr C = 432/180
Gr C = 2,4 gram
n C = Gr C/Ar C
n C = 2,4/12
n C = 0,2 mol
x C = n C × L
x C = 0,2 × 6,02 ×10²³
× C = 1,204 × 10²³ partikel

Gr H = x Ar H × Gr C6H12O6/Mr C6H12O6
Gr H = 12 × 1 × 6/180
Gr H = 72/180
Gr H = 0,03 gram
n H = Gr H/Ar H
n H = 0,03/1
n H = 0,03 mol
x H = n H × L
x H = 0,03 × 6,02 × 10²³
x H = 0,1806 × 10²³ partikel

Gr O = x Ar O × Gr C6H12O6/Mr C6H12O6
Gr O = 6 × 16 × 6/180
Gr O = 576/180
Gr O = 3,2 gram
n O = Gr O/Ar O
n O = 3,2/16
n O = 0,2 mol
x O = n O × L
x O = 0,2 × 6,02 × 10²³
x O = 1,204 × 10²³ partikel