ttik A(-9,-7,4), B(-4,-3,1) dan C(6,5,p-2) segaris untuk nilai p

AB
= B - A
= (-4,-3,1) - (-9,-7,4)
= (5,4,-3)

BC
= C - B
= (6,5,p-2) - (-4,-3,1)
= (10,8,p-3)

segaris, maka
AB = k.BC
(5,4,-3) = k(10,8,p-3)

10k = 5
k = 1/2

1/2 (p-3) = -3
p - 3 = -6
p = -3

Mapel : Matematika
Kelas : X SMA
Bab : Vektor

Pembahasab :
AB = b - a
AB = [-4 -3 1] - [-9 -7 4]
AB = [5 4 -3]

BC = c - b
BC = [6 5 (p - 2)] - [-4 - 3 1]
BC = [10 8 (p - 3)]

Karena Segaris / Kolinear
AB = k . BC
[5 4 -3] = k . [10 8 (p - 3)]

5 = 10k
k = 1/2

1/2(p - 3) = -3
p - 3 = -6
p = -6 + 3
p = -3