Dik : f(x)= 2x -4, f'(3)= -4 dan f(0)= 5. Nilai f(3) adalah... A.-32 b.-27 c.-22 d.-18 e.-7

f"(x) = 2x - 4

f'(x) = x^2 - 4x + c
f'(3) = 3^2 - 4(3) + c
-4 = 9 - 12 + c
c = -1
f'(x) = x^2 - 4x - 1

f(x) = (1/3)x^3 - 2x^2 - x + c
f (0) = (1/3)(0)^2 - 2(0)^2 - 0 + c
5 = 0 - 0 - 0 + c
c = 5
f(x) = (1/3)x^3 - 2x^2 - x + 5

f(3) = (1/3)(3)^3 - 2(3)^2 - 3 + 5
= 9 - 18 - 3 + 5
= -7

Jawaban E