tentukan ph 10ml larutan nh4oh 0.001M kb=1,8x10*-5
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tentukan ph 10ml larutan nh4oh 0.001M kb=1,8x10*-5
1 Jawaban
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1. Jawaban ionkovalen
OH- = akar Kb Mb
= akar 18.10^-6 x 10^-3
= akar 1,8.10^-8
= 1,34.10^-4 M
pOH = 4 - log 1,34
pH = 10 + log 1,34