tolong bantu kak sama cara ngerkakan nya

^tanda pangkat
19) f(x) = 2x²/3√x
f(x) = (2/3)x^(2-1/2)
f(x) = (2/3)x^(3/2)
f'(x) = (2/3)(3/2)x^(3/2 - 1)
f'(x) = x^(1/2)
f'(x) = √x

20) f(x) = 3x² + 7x
f'(x) = 6x + 7

21) f(x) = (5x²+10)³
f'(x) = (10x)(3)(5x²+10)²
f'(x) = 30x(5x² + 10)²

19) f(x) = (2x^2)/(3 akar x)
= 2/3 (x^2-1/2)
= 2/3 (x^3/2)
f'(x) = 2/3 (3/2) (x^3/2-1)
= 6/6 (x^1/2)
= x^1/2
= akar x (c)
20) f(x) = 3x^2 + 7x
f'(x) = 3(2)x^2-1 + 7x^1-1
= 6x^1 + 7x^0
= 6x + 7 (a)
21) f(x) = (5x^2 + 10)^3
f(x) = 5x^2 + 10 => f'(x) = 5(2)x^2-1 = 10x
f'(x) = 3(5x^2 + 10)^3-1 (10x)
= 30x(5x^2 + 10)^2 (b)