pH campuran 100 mL larutan CH3COOH 0,2 M yang reaksinya dengan 200 mL larutan KOH 0,05 M Adalah...(Ka CH3 COOH =1*10

CH3COOH = 100 ml × 0,2 m = 20 mmol ( asam)
KOH = 200 ml × 0,05 m = 10 mmol( basa)
Ka = 1× 10^-5
ch3cooh + koh ---> k ch3coo + h2o
mula2 : 20 10 - -
reaksi : 10 10 10 10
sisa: 10 - 10 10

[H] = ka × nasam/ngaram
= 1× 10 × 10/10
= 1 × 10^-5
Ph = - log [H]
= - log 1× 10^-5
= 5 - log 1