diketahui f(x)=x-3 dan (fog)^-1=1+3x/x-2 makan g^-1=...

f(x) = x - 3
x - 3 = y
x = y + 3
f-¹(x) = x + 3
(fog)-¹(x) = g-¹of-¹(x) = 1+3x / x-2
g-¹(x + 3) = (1 + 3x) / (x - 2)
misal p = x + 3
p - 3 = x
x = p - 3
g-¹(p) = (1 + 3(p-3)) / (p - 3 - 2)
g-¹(p) = (1 + 3p - 9) / (p - 5)
g-¹(p) = (3p - 8) / (p - 5)
g-¹(x) = (3x - 8) / (x - 5)

f(x)= x-3
f^-1 (x) = x+3
(f^-1 o g^-1) = 1+3x / x-2

(fog)^-1 = f^-1 (g^-1)

● f^-1 (g^-1) = 1+3x / x-2
(g^-1) + 3 = 1+3x / x -2
(g^-1) = 1+3x / x-2 -3
(g^-1) = 1+3x-3(x-2) / x-2
(g^-1) = 1+3x-3x+6 / x-2
(g^-1) = 7/x-2