²log6+²log8-²log12=berapa hasilnya

Pakai 4 sifat logaritma
^a log b + ^a log c = ^a log bc
^a log b - ^a log c = ^a log b/c
^a log b^n = n . ^a log b
^a log a = 1

^2 log 6 + ^2 log 8 - ^2 log 12
= ^2 log (6 × 8 ÷ 12)
= ^2 log 4
= ^2 log 2^2
= 2 × ^2 log 2
= 2 × 1
= 2

^2 log 6 + ^2 log 8 - ^2 log 12
= ^2 log [6 × 8 : 12]
= ^2 log 4
= ^2 log 2^2
= 2 × ^2 log 2
= 2 × 1
= 2