Diketahui f(x) = 2x³ + 2x² - x + 5. Nilai dari f'(-3) =....

f(x) = 2x^3 + 2x^2 -x + 5

f'(x) = 2.3 x^3-1 + 2.2 x^2-1 - 1.1 x^1-1
f'(x) = 6x^2 + 4x - 1
f'(-3) = 6 (-3)^2 + 4 . -3 -1
= 54 -12 -1
= 41

deferensial kan ?
F(x) = 2x³ + 2x² - x + 5
F'(x) = 6x² + 4x - 1
F'(-3)= 6(-3)² + 4(-3) - 1
F'(-3)=54-12-1 = 41

jika belum paham lihat rumusnya di buku atau di google,
Semoga terbantu