tentukan nilai x yang memenuhi persamaan logaritma 3log2x-3logx^2-3=0 tolong dibantu ya...

³log2x - ³logx²-3 = 0
³log(2x/(x²-3)) = ³log1
2x/(x²-3) = 1
2x = x²-3
x² - 3 - 2x = 0
x² - 2x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 dan x = -1