ph larutan H2SO4 (0,04M)
Kimia
kimsabu
Pertanyaan
ph larutan H2SO4 (0,04M)
1 Jawaban
-
1. Jawaban asrinsr
H2SO4 = asam kuat
[H+] = valensi H2SO4 x M
= 2 x 0,04
= 8 x 10^-2
ph = - log H+
= - log (8 x 10^-2)
= 2 - log 8