panjang cd = a.12✓39 b.4✓39 c.3✓39 d.4✓13 e.2✓39
Matematika
Danielkw0k
Pertanyaan
panjang cd =
a.12✓39
b.4✓39
c.3✓39
d.4✓13
e.2✓39
a.12✓39
b.4✓39
c.3✓39
d.4✓13
e.2✓39
1 Jawaban
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1. Jawaban indra0011
pertama cari dulu panjang BD pake aturan cosinus.
BD = akar(AB^2 + AD^2 - 2 AB AD cos60)
BD = akar(12^2 + 16^2 - 192)
BD = akar(208) = 4 akar(13)
lalu bisa di cari panjang DC, dimana
tan 60 = DC/BD
akar(3) = DC/ 4 akar(13)
DC = akar(3) x 4 akar(13)
DC = 4 akar(39)