jika pH larutan Ca(OH)2 jenuh = 11. Tentukan Ksp Ca(OH)2 !

pH = 14 + log [OH-]
11 = 14 + log [OH-]
[OH-] = 0,001 M

Ca(OH)2 → Ca2+ + 2OH-

Ksp = [Ca2+][OH-]²
Ksp = (0,001)(0,002)²
Ksp = 4 × 10^(-9)