nilai ekstrim dari f(x)= -2x²+10x dimohon bntuannya fast

Bab Fungsi Kuadrat
Matematika SMP Kelas VIII

f(x) = -2x² + 10x
a = -2; b = 10; c = 0

sumbu simetri = x = -b/2a
sumbu simetri = x = -10 / (2 . -2)
sumbu simetri = x = 5/2

f(x) = -2x² + 10x
f(5/2) = -2 . (5/2)² + 10 . (5/2)
f(5/2) = -2 . 25/4 + 25
f(5/2) = -25/2 + 50/2
f(5/2) = 25/2
f(5/2) = 12 1/2
f(5/2) = 12,5

jadi, nilai ekxtrim = 25/2