jika sin a = 4/5 tentukan sec a, csc a dan tan a

sin a = de/mi
de = 4
mi = 5
Maka sa = 3 (Triple Phytagoras)

sec a = mi/sa = 5/3
csc a = mi/de = 5/4
tan a = de/sa = 4/3

Bab Trigonometri
Matematika SMA Kelas X

sin a = 4/5

cos a = √(1 - sin² a)
cos a = √(1 - (4/5)²)
cos a = √(1 - 16/25)
cos a = √((25 - 16)/25)
cos a = √(9/25)
cos a = 3/5

1] sec a = 1 : cos a
sec a = 1 : 3/5
sec = 5/3

2] cosec a = 1 : sin a
cosec a = 1 : 4/5
cosec a = 5/4

3] tan a = sin a : cos a
tan a = 4/5 : 3/5
tan a = 4/5 x 5/3
tan a = 4/3