tolong dibantu ya 1. hasil dari integral 5x-1 per (5x^2-2x+6)^7 dx adalah.. 2. nilai integral dari -1 sampai 2 (x-1)(3x+1)dx 3. hasil integral (sin^2 5x cos 5x)

[tex]\displaystyle \int\frac{5x-1}{(5x^2-2x+6)^7}$ $dx \\ u=5x^2-2x+6,$ $du=10x-2$ $dx \\ \frac{du}{2}=5x-1$ $dx \\ \\ \displaystyle \int\frac{\frac{1}{2}}{u^7}$ $du \\ \int\frac{u^{-7}}{2}$ $du=\frac{u^{-7+1}}{2(-7+1)} = \frac{u^{-6}}{-12}+C=-\frac{1}{12u^6}+C \\ \\ \displaystyle -\frac{1}{12(5x^2-2x+6)^6}+C[/tex]

[tex]\int_{-1}^2(x-1)(3x+1)$ $dx \\ \int_{-1}^23x^2-2x-1$ $dx \\ x^3-x^2-x]_{-1}^2 \\ (2^3-2^2-2)-((-1)^3-(-1)^2-(-1)) \\ (8-4-2)-(-1-1+1)=2-(-1)=3[/tex]

[tex]\int \sin^2{5x}\cos{5x}$ $dx \\ \int \frac{\sin^2{5x}}{5}$ $d\sin{5x} \\ \displaystyle \frac{\sin^3{5x}}{3.5}+C=\frac{\sin^3{5x}}{15}+C[/tex]