apa cara dan hasil dari 3:(x-10)+4:(x-3)

[tex] \frac{3}{x-10} + \frac{4}{x-3} = \frac{3(x-3)+4(x-10)}{(x-10)(x-3)} = \frac{3x-9+4x-40}{ x^{2} -13x+30} [/tex]
=[tex] \frac{7x-49}{x^{2} -13x+30} [/tex]