Matematika

Pertanyaan

dengan aturan rantai, tentukan turunan fungsi f(x) =3(x²-2x)5

1 Jawaban

  • f(x) = 3(x^2 - 2x)^5
    y = 3(x^2 - 2x)^5

    Misal
    u = x^2 - 2x => du/dx = 2x - 2

    y = 3u^5 => dy/du = 15u^4 = 15(x^2 - 2x)^4

    f'(x) = dy/dx
    = dy/du . du/dx
    = 15(x^2 - 2x)^4 . (2x - 2)
    = (30x - 30)(x^2 - 2x)^4

    = 30(x - 1)(x^2 - 2x)^4

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