jika 6+8+10+12+....+40=60p-6 maka nilai p
Matematika
ais209
Pertanyaan
jika 6+8+10+12+....+40=60p-6 maka nilai p
2 Jawaban
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1. Jawaban dnnyz07
Pakai rumus deret aritmatika,
a = 6
b = 8 - 6 = 2
Un = a + (n - 1)b
40 = 6 + (n - 1) 2
40 - 6 = (n-1)2
34 = (n - 1)2
34/2 = n - 1
17 = n - 1
n = 18
Sn = n/2 ( a+ Un)
S18 = 18/2 (6 + 40)
S18 = 9(46)
S18 = 414
414 = 60p - 6
414 + 6 = 60p
60p = 420
p = 420/60
p = 7 -
2. Jawaban Anonyme
Bab Pola Bilangan
Matematika SMP Kelas VII
6 + 40 = 46
8 + 38 = 46
10 + 36 = 46
12 + 34 = 46
14 + 32 = 46
16 + 30 = 46
18 + 28 = 46
20 + 26 = 46
22 + 24 = 46
------- +
414
414 = 60p - 6
60p = 414 + 6
p = 420 / 60
p= 7