Matematika

Pertanyaan

jika 6+8+10+12+....+40=60p-6 maka nilai p

2 Jawaban

  • Pakai rumus deret aritmatika,
    a = 6
    b = 8 - 6 = 2

    Un = a + (n - 1)b
    40 = 6 + (n - 1) 2
    40 - 6 = (n-1)2
    34 = (n - 1)2
    34/2 = n - 1
    17 = n - 1
    n = 18

    Sn = n/2 ( a+ Un)
    S18 = 18/2 (6 + 40)
    S18 = 9(46)
    S18 = 414

    414 = 60p - 6
    414 + 6 = 60p
    60p = 420
    p = 420/60
    p = 7
  • Bab Pola Bilangan
    Matematika SMP Kelas VII

    6 + 40 = 46
    8 + 38 = 46
    10 + 36 = 46
    12 + 34 = 46
    14 + 32 = 46
    16 + 30 = 46
    18 + 28 = 46
    20 + 26 = 46
    22 + 24 = 46
                   ------- +
                    414
     
    414 = 60p - 6
    60p = 414 + 6
    p = 420 / 60
    p= 7

Pertanyaan Lainnya