ΔPQR, sudut P=45°, sdt Q=105°, p=6√6 maka r = ...?

sudut R = 180° -(45°+105°)
= 180°- 150° = 30°

cari panjang r menggunakan aturan sinus:
p/sin P = r/sin R
6√6/sin 45° = r/sin 30°
6√6/(1/2√2) = r/(1/2)
1/2√2 r = 6√6 x 1/2
1/2√2 r = 3√6
r = 3√6 x 2/√2
r = 6√6/√2 x √2/√2
r = 6√12/2
r = 3√12
r = 3 √4x3
r = 3x2√3
r = 6√3

sudut R = 180 - (45 + 105)
= 180 - 150 = 30 derajat
maka r
p/ sin P = r/ sin R
6akar6/sin45 = r/sin30
6akar6/1/2 akar2 = r/1/2
r = (6akar6 × 1/2) /1/2 akar2
r = 3akar6/1/2 akar2
r = (6 akar6×akar2)/akar2 x akar2
r = (6 akar 12)/2
r = 6 akar 3