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Pertanyaan

tolong dibantu ya pliss sebisanya saja
tolong dibantu ya pliss sebisanya saja

1 Jawaban

  • 7 . Mr CuSO4.5H2O
    CuSO4 . 5H2O  = 63,5 + 32 + 4.16 +5(2.1+ 16)
    Mr = 63,5 + 32 + 64 + 90
    Mr =249,5

    8.Mr Fe2(SO4)3 = 400
    ( Ar Fe x2) + ( 96 x 3 ) = 400
    ( Ar Fe x2) = 400 - 288
    Ar Fe = 112 / 2 = 56

    9 . N2H4
    mol N2H4 = gr / mr = 8 / 30 = 0,27
    Jp = mol X avogadro
    jp  = 0,27 x 6,02 x 10^23 = 1,63 x 10^23

    10 , Cu
    mol Cu = 0,1 mol
    Jp = mol X avogadro
    jp  = 0,1 x 6,02 x 10^23 = 6,02 x 10^22

    11.
    NO2
    mol NO2 = 2 mol
    Jp = mol X avogadro
    jp  = 2 x 6,02 x 10^23 = 1,204 x 10^24

    12. jp = mol x A
    mol = jp / A = 
    1,204 x 10^23 / 6,02 x 10^23 = 0,2 mol