Matematika

Pertanyaan

x+y+z = 13 dan 2y = 3y = 4z. Nilai x+y-z adalah

1 Jawaban

  • x + y + z = 13 ................ x 12
    12x + 12y + 12z = 156
    2x = 3y = 4z ................. x 6
    12x = 18y = 24z
    18y + 12y + 12z = 156
    2x = 3y = 4z ................. x 3
    6x = 9y = 12z
    18y + 12y + 9y = 156
    39y = 156
    y = 4
    18y + 12y + 12z = 156
    30x4 + 12z = 156
    12z = 36
    z = 3
    x + 4 + 3 = 13
    x = 6

    Mari cek kalau betul nilainya :
    2x = 3y = 4z
    2x6 = 3x4 = 4x3 = 12.

    Nilai x + y - z = 6 + 4 - 3 = 7

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