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hitung ph larutan H2CO3 0,1 M dengan Ka = 10^-5

1 Jawaban

  • H2CO3 0,1 M Ka = 10^-5

    [H^+] = √Ka×Ma
    [H^+] = √10^-5 × 0,1
    [H^+] = √10^-6
    [H^+] = 10^-3

    pH = - log [H^+]
    pH = - log 10^-3
    pH = 3
    semoga puas

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