Jika g(x) = x-1 dan (f.g)(x) = 2x²-4x+3 maka fungsi f(x)

g(x) = x - 1
(f○g)(x) = 2x^2 - 4x + 3
f○(g(x)) = f○(x - 1) = 2x^2 - 4x + 3
f(x) = 2x^2
f○(g(x)) = 2(x - 1)^2 = 2[x^2 - 2x + 1]
= 2x^2 - 4x + 2
[2x^2 - 4x + 3] - [2x^2 - 4x + 2] = 1
f(x) = 1
f(x) = 2x^2 + f(x) = 1
=> f(x) = 2x^2 + 1
Jadi fungsi f(x) = 2x^2 + 1