jika f(x)=1000-100x+10x², maka f'(x) adalah

[tex] Jika ~ f(x) = ax^{n} \\ Maka ~ f'(x) = an . x^{n-1} \\ \\\\ f(x) = 1.000 - 100x + 10x^{2} \\ \\ f'(x) = 1000 . 0x^{0-1} - 100.1x^{1-1} + 10.2.x^{2-1} \\ f'(x) = -100 + 20x \\ f'(x) = 20x - 100 [/tex]

Mapel : Matematika
Kelas : XI SMA
Bab : Differensial

Pembahasan :
Rumus f(x) = ax^n
f'(x) = n . ax^(n - 1)

f(x) = 1000 - 100x + 10x²
f'(x) = 0 - 100 + 20x
f'(x) = 20x - 100