soal limit.. tolong jawab yaa dengan caranya

Bab Limit
Matematika SMA Kelas XI

lim (√(-2x + 3)² - 3²) / ((x² + 3x) (√(-2x + 3) + 3)
x→-3
= lim ((-2x + 3) - 9) / ((x² + 3x) (√(-2x + 3) + 3)
  x→-3
= lim (-2x - 6) / (x (x + 3) (√(-2x + 3) + 3))
  x→-3
= lim (-2 (x + 3) / (x (x + 3) (√(-2x + 3) + 3)
  x→-3
= -2 / (-3 (√(-2 . -3 + 3) + 3))
= -2 / (-3 (√(6 + 3) + 3))
= 2 / (3 . 6)
= 1/9

jawabannya B