Persamaan bayangan garis 3x+y-2 = 0

Transformasi
(x' , y' ) = T2oT1 (x,y)

T2 o T1 = |2..0||0...2| [0...-1||1..0] = [0...-2||2...0]

x' = -2y --> y = - 1/2 x'
y' =  2x --> x = 1/2 y'
sub ke garis 3x + y  - 2= 0
3(1/2 y') + (-1/2x') -2 =0
3/2 y - 1/2 x - 2 = 0
3y - x - 4= 0 atau x - 3y + 4 = 0