jika y= cotan (3-t^2) dan x=2t^2+1 maka dy/dx ...

y = cot (3 - t²)
dy/dx  = 2t  .csc² (3 - t²)

x= 2t² + 1
dx/dt = 4t
dt/dx  = 1/(4t)

dy/dx = dy/dt. dt/dx
dy/dx = 2t. csc² (3 - t²) ( 1/ (4t))
dy/dx = 1/2  csc² (3- t²)
dy/dx = 1/ (2 sin ² (3 - t²) )