Tentukan ph H2SO40,04M

Dik : [H2SO4] : 0,04 M = 4 x 10^-2
Dit : pH H2SO4
Jawab :
H2SO4 --> 2H + SO4
[H+] = x [HA]
[H+] = 2 x 4 x 10^-2
= 8 x 10-2

pH = -log [H+]
= -log 8 x 10^-2
= 2-log 8
= 1,09