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Tentukan pH larutan-larutan asam kuat berikut ini
a. 100Ml HCI 10–²
B. Larutan NaOH 0,1 M

1 Jawaban

  • A. 100 mL HCl 10-²M
    HCl -> H+ + Cl-
    10-²M
    [H+] = koefisien H+/Koefisien HCl = 1/1 x 10-²M
    = 10-²M
    pH = -log [H+]
    = -log 10-²
    = 2

    B. Larutan NaOH 0,1 M
    NaOH -> Na+ + OH-
    0,1M
    [OH-] = 0,1 M
    pOH = -log [OH-]
    = -log 10-¹
    = 1
    pH = 14 - pOH
    = 14 - 1
    = 13

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