Nilai maksimum dari fungsi f(t) = t + akar a - 2t adalah 10, maka nilai a adalah

nilai maksimum

f(t) = t + √(a- 2t)
f' (t)= 0
1+ 1/2 (a - 2t)⁻¹/² (-2) = 0
1 - (a - 2t)⁻¹/² =0
(a - 2t)⁻¹/² = 1
1/ (a - 2t)¹/² = 1
(a - 2t)¹/² = 1
a - 2t = 1
a = 1 + 2t

f(t) = t + √(a - 2t)
f(t)= 10
t + √(1 + 2t - 2t)  = 10
t + 1 = 10
t = 9

a = 1 + 2t
a = 1 + 2(9)
a= 19