jika 200mL larutan KOH 0,4M dicampur dengan 800mL larutan Ca(OH)2 0,075M maka pH larutan campuran menjadi?

n KOH = 200 x 0,4 = 80
n Ca(OH)2 = 800x0,075 = 60

KOH + Ca(OH)2 ----> KOCa+ + H2O
m: 80. 60. 0
b: 60. 60- 60
-------------------------------------------+
s: 20. - 60

[H+] = Ka x n KOH/ n Ca(OH)
= 10^-5 x 20/6ⁿ
= 0,33x10^-5
pOH : -log 0,33x10^-5
: 5-log 0,33
pH: 14- (pOH)
: 14- (5-log 0,33)
: 9-log 0,33.