Matematika

Pertanyaan

Limit cos² t / 1+sin t = ?
t⇒0

1 Jawaban

  • [tex] \lim_{t\to0}\frac{cos^{2}t}{1+sint}[/tex]
    => [tex]lim_{t\to0}\frac{1-sin^{2}t}{1+sint}[/tex] (Ingat cos²t = 1 - sin²t)
    => [tex]lim_{t\to0}\frac{(1+sint)(1-sint)}{1+sint}[/tex]
    => [tex]lim_{t\to0}1-sint=1-sin0=1-0=1[/tex]

    Semoga membantu

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